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If (a=5) and (r=3) what is the fourth term of the geometric progression?
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Answer and explanation
Correct answer: 135
The nth term of a geometric progression is \(T_n=ar^{n-1}\). Therefore, \(T_4=5\times3^{4-1}=5\times27=135\). The value 45 is the third term because \(5\times3^2=45\). Exam tip: for the fourth term, use the exponent \(4-1=3\).
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What is the correct answer to this question?
135
Why is this the correct answer?
The nth term of a geometric progression is \(T_n=ar^{n-1}\). Therefore, \(T_4=5\times3^{4-1}=5\times27=135\). The value 45 is the third term because \(5\times3^2=45\). Exam tip: for the fourth term, use the exponent \(4-1=3\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Geometric Progression.
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