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If \(a=2\) and \(r=6\) what is the third term of the geometric progression?
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Answer and explanation
Correct answer: 72
The \(n\)th term of a geometric progression is \(T_n=ar^{n-1}\). Therefore, \(T_3=ar^2=2\times6^2=2\times36=72\). Here, \(36\) is only the value of \(r^2\); it must be multiplied by the first term, \(a=2\). Exam tip: for the third term, use \(ar^2\) directly.
Frequently asked questions
What is the correct answer to this question?
72
Why is this the correct answer?
The \(n\)th term of a geometric progression is \(T_n=ar^{n-1}\). Therefore, \(T_3=ar^2=2\times6^2=2\times36=72\). Here, \(36\) is only the value of \(r^2\); it must be multiplied by the first term, \(a=2\). Exam tip: for the third term, use \(ar^2\) directly.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Geometric Progression.
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