If (a=12) and (r=2) what will be the sixth term of the geometric progression?
Answer and explanation
Correct answer: 384
The nth term of a geometric progression is \(T_n=ar^{n-1}\). Therefore, \(T_6=12\times2^{6-1}=12\times2^5=12\times32=384\). The value \(288\) can result from an error in evaluating the power or multiplication. Exam tip: for the sixth term, always use the exponent \(6-1=5\).
Frequently asked questions
What is the correct answer to this question?
384
Why is this the correct answer?
The nth term of a geometric progression is \(T_n=ar^{n-1}\). Therefore, \(T_6=12\times2^{6-1}=12\times2^5=12\times32=384\). The value \(288\) can result from an error in evaluating the power or multiplication. Exam tip: for the sixth term, always use the exponent \(6-1=5\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Geometric Progression.
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