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For a geometric progression with (a=3) and (a_6=96), if (r) is positive, what is (r)?

Answer and explanation

Correct answer: \(2\)

The \(n\)th term of a GP is \(a_n=ar^{n-1}\). Thus, \(a_6=3r^5=96\), so \(r^5=32=2^5\). Since \(r\) is positive, \(r=2\). If \(r=3\), then \(3\times3^5\) is not equal to 96. Exam tip: for the sixth term, the exponent of \(r\) is \(6-1=5\).

Related tags

Geometric ProgressionGp Nth TermCommon RatioSequences And ProgressionsClass 9 MathematicsMathematicsClass 9 Mcq

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