At which point does the line (y=-4x+13) cut the (y)-axis?
Answer and explanation
Correct answer: \((0,13)\)
At every point on the \(y\)-axis, the \(x\)-coordinate is \(0\). Substituting \(x=0\) in \(y=-4x+13\) gives \(y=13\), so the line meets the \(y\)-axis at \((0,13)\). The point \((13,0)\) lies on the \(x\)-axis, so it cannot be the \(y\)-intercept. Exam tip: In \(y=mx+c\), the \(y\)-intercept is \((0,c)\).
Frequently asked questions
What is the correct answer to this question?
\((0,13)\)
Why is this the correct answer?
At every point on the \(y\)-axis, the \(x\)-coordinate is \(0\). Substituting \(x=0\) in \(y=-4x+13\) gives \(y=13\), so the line meets the \(y\)-axis at \((0,13)\). The point \((13,0)\) lies on the \(x\)-axis, so it cannot be the \(y\)-intercept. Exam tip: In \(y=mx+c\), the \(y\)-intercept is \((0,c)\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Slope and y-intercept.
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