Correct answer: A. (a_n=6n)
Explanation: The direct answer is option A, \(a_n=6n\). Look at the terms: 6, 12, 18, and 24. They are respectively \(6\times1\), \(6\times2\), \(6\times3\), and \(6\times4\). Therefore the nth term is \(6\times n=6n\). This is also an arithmetic progression with first term 6 and common difference 6: \(a_n=6+(n-1)6=6n\). Option A is correct because it gives 6 for \(n=1\), 12 for \(n=2\), and so on. Option B, \(n+6\), gives 7 when \(n=1\), so it does not even give the first term. Option C, \(12n\), gives 12 for the first term, which is too large. Option D, \(6n-1\), gives 5 for the first term and therefore fails. The memory trick is: when the sequence is 6 times 1, 2, 3, 4, its nth term is 6 times n.