Correct answer: C. (9)th
Explanation: The answer is option C, the 9th term. We need the first term for which \(a_n<0\). Given \(a_n=25-3n\), test the boundary: \(25-3n<0\), so \(25<3n\), hence \(n>25/3=8\frac{1}{3}\). The smallest whole-number position is \(n=9\). Direct checking gives \(a_8=25-24=1\), still positive, and \(a_9=25-27=-2\), negative. Option A, 7th, gives 4, positive. Option B, 8th, gives 1, positive. Option C, 9th, gives -2 and is the first negative term. Option D, 10th, gives -5, which is negative but not the first one. The key is to use a strict inequality because “negative” means less than zero, not equal to zero. Memory cue: find the first integer after the expression crosses below zero.