What are the (y)-intercept and slope in (12x+5y-65=0)?समीकरण (12x+5y-65=0) में (y)-अवरोध और ढाल कौन से हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (y)-intercept (13), slope (-\frac{12}{5})(y)-अवरोध (13), ढाल (-\frac{12}{5})
From (5y=-12x+65), (y=-\frac{12}{5}x+13). So the (y)-intercept is (13) and slope is (-\frac{12}{5}).(5y=-12x+65) से (y=-\frac{12}{5}x+13) मिलता है। इसलिए (y)-अवरोध (13) और ढाल (-\frac{12}{5}) है।
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