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If (y=-10x+s) and (y=7x-19) have the same (y)-intercept, what will (s) be?यदि (y=-10x+s) और (y=7x-19) का (y)-अवरोध समान है, तो (s) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: -19-19
In the form \(y=mx+c\), the constant term \(c\) is the \(y\)-intercept. The \(y\)-intercept of \(y=-10x+s\) is \(s\), while that of \(y=7x-19\) is \(-19\). Since the intercepts are equal, \(s=-19\). Note that \(-10\) is the slope of the first line, not its \(y\)-intercept. Exam tip: Put \(x=0\) to find the \(y\)-intercept.रेखा के रूप \(y=mx+c\) में \(y\)-अवरोध स्थिर पद \(c\) होता है। पहली रेखा \(y=-10x+s\) का \(y\)-अवरोध \(s\) है, जबकि दूसरी रेखा \(y=7x-19\) का \(y\)-अवरोध \(-19\) है। दोनों अवरोध समान हैं, इसलिए \(s=-19\)। \(-10\) पहली रेखा की ढाल है, \(y\)-अवरोध नहीं। परीक्षा टिप: \(y\)-अवरोध ज्ञात करने के लिए \(x=0\) रखें।
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