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If (y=(r+10)x+(r-6)) passes through the origin, what will be its slope?यदि (y=(r+10)x+(r-6)) मूल बिंदु से गुजरती है, तो इसकी ढाल क्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(16\)\(16\)
Since the line passes through the origin \((0,0)\), put \(x=0\) and \(y=0\). Its constant term must be zero: \(r-6=0\). Hence, \(r=6\). The slope is the coefficient of \(x\), so \(r+10=6+10=16\). Option \(6\) is the value of \(r\), not the slope. Exam tip: in \(y=mx+c\), \(m\) is the slope and \(c\) is the y-intercept.रेखा मूल बिंदु \((0,0)\) से गुजरती है, इसलिए \(x=0\) और \(y=0\) रखने पर स्थिर पद शून्य होना चाहिए: \(r-6=0\)। अतः \(r=6\)। अब ढाल \(x\) का गुणांक है, अर्थात \(r+10=6+10=16\)। विकल्प \(6\) केवल \(r\) का मान है, ढाल नहीं। परीक्षा टिप: \(y=mx+c\) में ढाल \(m\) और y-अवरोध \(c\) होता है।
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