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If (y=(3u-2)x+(u+6)) has (y)-intercept (16), what is the slope?यदि (y=(3u-2)x+(u+6)) का (y)-अवरोध (16) है, तो ढाल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 2828
A line in the form y = mx + c has y-intercept c. Here, the y-intercept is u + 6. So, u + 6 = 16, giving u = 10. Therefore, the slope is 3u - 2 = 3(10) - 2 = 28. Option 26 can result from an incorrect subtraction. Exam tip: to find the y-intercept, put x = 0.रेखा का रूप y = mx + c होता है, जहाँ y-अवरोध c होता है। यहाँ y-अवरोध u + 6 है। अतः u + 6 = 16, इसलिए u = 10। अब ढाल 3u - 2 = 3(10) - 2 = 28 है। 26 विकल्प तब मिलता यदि घटाव की गणना गलत की जाए। परीक्षा टिप: y-अवरोध ज्ञात करने के लिए x = 0 रखें।
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