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The line (y=(n-7)x+(4n-5)) has (y)-intercept (23). What is its slope?रेखा (y=(n-7)x+(4n-5)) का (y)-अवरोध (23) है। इसकी ढाल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 00
A line in the form y = mx + c has y-intercept c. Here, 4n - 5 = 23, so 4n = 28 and n = 7. Therefore, the slope is n - 7 = 7 - 7 = 0. Option 1 is not correct because substituting n = 7 makes the coefficient of x equal to zero. Exam tip: In y = mx + c, the coefficient of x is always the slope.रेखा का रूप y = mx + c होता है, जहाँ y-अवरोध स्थिर पद c होता है। यहाँ 4n - 5 = 23, अतः 4n = 28 और n = 7। इसलिए ढाल n - 7 = 7 - 7 = 0 है। विकल्प 1 ढाल नहीं है, क्योंकि n का मान 7 रखने पर x का गुणांक शून्य हो जाता है। परीक्षा टिप: y = mx + c में x का गुणांक हमेशा ढाल होता है।
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