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If (y=(r-4)x+(r+6)) passes through the origin, what will be its slope?यदि (y=(r-4)x+(r+6)) मूल बिंदु से गुजरती है, तो इसकी ढाल क्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-10\)\(-10\)
The line is \(y=(r-4)x+(r+6)\). Since it passes through the origin \((0,0)\), substituting \(x=0\) and \(y=0\) gives \(r+6=0\). Hence, \(r=-6\). Therefore, the slope is \(r-4=-6-4=-10\). Note that \(-6\) is the value of the parameter \(r\), not the slope. Exam tip: in \(y=mx+c\), \(m\) is the slope and \(c\) is the y-intercept.रेखा का समीकरण \(y=(r-4)x+(r+6)\) है। मूल बिंदु \((0,0)\) से गुजरने पर \(x=0\) और \(y=0\) रखने से \(r+6=0\) मिलता है। अतः \(r=-6\)। इसलिए ढाल \(r-4=-6-4=-10\) होगी। \(-6\) पैरामीटर \(r\) का मान है, ढाल नहीं। परीक्षा टिप: \(y=mx+c\) में ढाल \(m\) और y-अवरोध \(c\) होता है।
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