0 reads0 ratings0 helpful
If (y=2x+(v-4)) and (y=(v+1)x+5) have the same (y)-intercept, what is the slope of the second line?यदि (y=2x+(v-4)) और (y=(v+1)x+5) का (y)-अवरोध समान है, तो दूसरी रेखा की ढाल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(10\)\(10\)
The y-intercept of the first line is \(v-4\), while that of the second line is \(5\). Since the y-intercepts are equal, \(v-4=5\), so \(v=9\). The slope of the second line \(y=(v+1)x+5\) is \(v+1=9+1=10\). Note that \(9\) is the value of \(v\), not the slope. Exam tip: in \(y=mx+c\), \(m\) is the slope and \(c\) is the y-intercept.पहली रेखा का \(y\)-अवरोध \(v-4\) है और दूसरी रेखा का \(y\)-अवरोध \(5\) है। समान \(y\)-अवरोध के लिए \(v-4=5\), अतः \(v=9\)। दूसरी रेखा \(y=(v+1)x+5\) की ढाल \(v+1=9+1=10\) होगी। \(9\) केवल \(v\) का मान है, ढाल नहीं। परीक्षा टिप: \(y=mx+c\) में \(m\) ढाल और \(c\) \(y\)-अवरोध होता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
