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If (y=(2t-3)x+(t+4)) has (y)-intercept (10), what is the slope?यदि (y=(2t-3)x+(t+4)) का (y)-अवरोध (10) है, तो ढाल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 99
In the form y = mx + c, the y-intercept is the constant term c. Here, the y-intercept is t + 4. From t + 4 = 10, we get t = 6. Therefore, the slope is 2t - 3 = 2(6) - 3 = 9. Option 6 is the value of t, not the slope. Exam tip: set x = 0 to identify the y-intercept.रेखा के रूप y = mx + c में y-अवरोध स्थिर पद c होता है। यहाँ y-अवरोध t + 4 है। t + 4 = 10 से t = 6 मिलता है। अतः ढाल 2t - 3 = 2(6) - 3 = 9 है। विकल्प 6, t का मान है, ढाल नहीं। परीक्षा टिप: y-अवरोध ज्ञात करने के लिए x = 0 रखें।
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