0 reads0 ratings0 helpful
If the line (y=(3k+2)x-5) has slope (11), what is (k)?यदि रेखा (y=(3k+2)x-5) की ढाल (11) है, तो (k) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(3\)\(3\)
In the slope-intercept form \(y=mx+c\), the coefficient of \(x\) is the slope \(m\). Here, the slope is \(3k+2\). Since \(3k+2=11\), we get \(3k=9\) and hence \(k=3\). Therefore, option B is correct. If \(k=4\), the slope would be \(14\), not \(11\). Exam tip: In \(y=mx+c\), identify \(m\) directly as the slope.रेखा के ढाल-अवरोध रूप \(y=mx+c\) में \(x\) का गुणांक ढाल \(m\) होता है। यहाँ ढाल \(3k+2\) है। दिया है \(3k+2=11\), अतः \(3k=9\) और \(k=3\)। इसलिए विकल्प B सही है। \(k=4\) रखने पर ढाल \(14\) होगी, जो \(11\) नहीं है। परीक्षा टिप: \(y=mx+c\) में \(m\) को सीधे ढाल पहचानें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
