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If a linear equation is in the form \(ax+by=c\), where \(b\ne0\), what is its slope?यदि एक रैखिक समीकरण का रूप \(ax+by=c\) है, जहाँ \(b\ne0\), तो उसकी ढाल कौन-सी होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-\frac{a}{b}\)\(-\frac{a}{b}\)
Rewrite \(ax+by=c\) as \(y=-\frac{a}{b}x+\frac{c}{b}\). In \(y=mx+k\), the coefficient of \(x\) is the slope, so it is \(-\frac{a}{b}\). \(\frac{c}{b}\) is the y-intercept, not the slope. Exam tip: compare with slope-intercept form.\(ax+by=c\) को \(y=-\frac{a}{b}x+\frac{c}{b}\) लिखते हैं। \(y=mx+k\) में \(x\) का गुणांक ढाल होता है, इसलिए ढाल \(-\frac{a}{b}\) है। \(\frac{c}{b}\) y-अवरोध है। परीक्षा टिप: पहले समीकरण को \(y=mx+k\) रूप में बदलें।
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