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If a line has slope (4) and cuts the (y)-axis at ( (0,-7) ), what is its equation?यदि रेखा की ढाल (4) है और वह (y)-अक्ष को ( (0,-7) ) पर काटती है तो समीकरण क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(y=4x-7\)\(y=4x-7\)
The slope-intercept form of a line is \(y=mx+c\), where \(m\) is the slope and \(c\) is the y-intercept. Here, \(m=4\) and \(c=-7\), so the equation is \(y=4x-7\). Although \(y=4x+7\) has the correct slope, its y-intercept is \(+7\). Exam tip: From the point \((0,c)\), read the sign of the y-intercept carefully.रेखा का ढाल-अवरोध रूप \(y=mx+c\) होता है, जहाँ \(m\) ढाल और \(c\) y-अवरोध है। यहाँ \(m=4\) तथा \(c=-7\) है, इसलिए समीकरण \(y=4x-7\) होगा। \(y=4x+7\) में ढाल सही है, लेकिन y-अवरोध \(+7\) है। परीक्षा टिप: बिंदु \((0,c)\) से y-अवरोध का चिन्ह सीधे पहचानें।
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