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The line (y=-5x+c) cuts the (y)-axis at ( (0,12) ). What is (c)?रेखा (y=-5x+c) (y)-अक्ष को ( (0,12) ) पर काटती है। (c) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(12\)\(12\)
To find the \(y\)-intercept of \(y=-5x+c\), put \(x=0\). Then \(y=-5(0)+c=c\). Since the given point is \((0,12)\), \(c=12\). The value \(-5\) is the slope of the line, not its \(y\)-intercept. Exam tip: in \(y=mx+c\), \(c\) is the \(y\)-intercept directly.रेखा \(y=-5x+c\) में \(y\)-अवरोध ज्ञात करने के लिए \(x=0\) रखते हैं। तब \(y=-5(0)+c=c\) मिलता है। दिया गया बिंदु \((0,12)\) है, इसलिए \(c=12\)। \(-5\) रेखा की ढाल है, \(y\)-अवरोध नहीं। परीक्षा टिप: \(y=mx+c\) में \(c\) सीधे \(y\)-अवरोध होता है।
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