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In the line \(y=\frac{2}{3}x+1\), how much will (y) increase when (x) increases by (9)?रेखा \(y=\frac{2}{3}x+1\) में (x) के (9) बढ़ने पर (y) कितना बढ़ेगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 66
The slope of \(y=\frac{2}{3}x+1\) is \(\frac{2}{3}\). Therefore, when \(x\) increases by 9, the increase in \(y\) is \(\frac{2}{3}\times 9=6\). Option 3 would result only if the slope were \(\frac{1}{3}\). Exam tip: for \(y=mx+c\), use \(\Delta y=m\Delta x\).रेखा \(y=\frac{2}{3}x+1\) की ढाल \(\frac{2}{3}\) है। अतः \(x\) में 9 की वृद्धि पर \(y\) में वृद्धि \(\frac{2}{3}\times 9=6\) होगी। विकल्प 3 केवल तब होता जब ढाल \(\frac{1}{3}\) होती। परीक्षा टिप: रैखिक समीकरण \(y=mx+c\) में \(y\) का परिवर्तन \(m\Delta x\) से ज्ञात करें।
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