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The line (y=-3x+c) cuts the (y)-axis at ( (0,9) ). What is (c)?रेखा (y=-3x+c) (y)-अक्ष को ( (0,9) ) पर काटती है। (c) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(9\)\(9\)
For the line \(y=-3x+c\), the \(y\)-axis has \(x=0\). Hence \(y=-3(0)+c=c\). Since the line meets the \(y\)-axis at \((0,9)\), its \(y\)-coordinate is 9, so \(c=9\). Here, \(-3\) is the slope, not the \(y\)-intercept. Exam tip: in \(y=mx+c\), \(c\) directly gives the \(y\)-intercept.रेखा \(y=-3x+c\) में \(y\)-अक्ष पर \(x=0\) होता है। इसलिए \(y=-3(0)+c=c\) होगा। दिया गया प्रतिच्छेद बिंदु \((0,9)\) है, अतः \(y=9\) और \(c=9\)। \(-3\) रेखा की ढाल है, \(y\)-अवरोध नहीं। परीक्षा टिप: \(y=mx+c\) में \(c\) सीधे \(y\)-अवरोध को दर्शाता है।
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