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If a line has slope (-8) and (y)-intercept (5), which equation is correct?यदि रेखा की ढाल (-8) और (y)-अवरोध (5) है तो समीकरण कौन सा होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(y=-8x+5\)\(y=-8x+5\)
The slope-intercept form of a line is \(y=mx+c\), where \(m\) is the slope and \(c\) is the \(y\)-intercept. Substituting \(m=-8\) and \(c=5\) gives \(y=-8x+5\). Option A has the correct \(y\)-intercept, but its slope is \(8\), not \(-8\). Exam tip: the coefficient of \(x\) is the slope, while the constant term is the \(y\)-intercept.रेखा का ढाल-अवरोध रूप \(y=mx+c\) होता है, जहाँ \(m\) ढाल और \(c\) \(y\)-अवरोध है। यहाँ \(m=-8\) तथा \(c=5\) रखने पर \(y=-8x+5\) मिलता है। विकल्प A में \(y\)-अवरोध सही है, लेकिन ढाल \(8\) है, \(-8\) नहीं। परीक्षा टिप: \(x\) का गुणांक ढाल बताता है और स्थिर पद \(y\)-अवरोध बताता है।
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