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What is the slope of the line \(y=-\frac{5}{9}x+8\)?रेखा \(y=-\frac{5}{9}x+8\) की ढाल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-\frac{5}{9}\)\(-\frac{5}{9}\)
The slope-intercept form of a line is \(y=mx+c\), where \(m\) is the slope and \(c\) is the y-intercept. Here, the coefficient of \(x\) is \(-\frac{5}{9}\), so the slope is \(-\frac{5}{9}\). The number \(8\) is the y-intercept, not the slope. Exam tip: In \(y=mx+c\), identify the number multiplying \(x\) as the slope.रेखा का ढाल-अवरोध रूप \(y=mx+c\) होता है, जहाँ \(m\) ढाल है और \(c\) y-अवरोध है। यहाँ \(x\) का गुणांक \(-\frac{5}{9}\) है, इसलिए ढाल \(-\frac{5}{9}\) है। \(8\) y-अवरोध है, ढाल नहीं। परीक्षा टिप: \(y=mx+c\) में \(x\) के साथ लगी संख्या को ढाल पहचानें।
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