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What is the (y)-intercept of the line \(y=\frac{9}{4}x+2\)?रेखा \(y=\frac{9}{4}x+2\) का (y)-अवरोध क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(2\)\(2\)
A line in the form \(y=mx+c\) has \(c\) as its \(y\)-intercept. Here, \(c=2\), so the \(y\)-intercept is \(2\); the line meets the \(y\)-axis at \((0,2)\). \(\frac{9}{4}\) is the slope, not the intercept. Exam tip: put \(x=0\) to find the \(y\)-intercept.रेखा का रूप \(y=mx+c\) होता है, जहाँ \(c\), \(y\)-अवरोध है। दी गई रेखा में \(c=2\) है, इसलिए \(y\)-अवरोध \(2\) है; अर्थात रेखा \(y\)-अक्ष को \((0,2)\) पर काटती है। \(\frac{9}{4}\) ढाल है, अवरोध नहीं। परीक्षा टिप: \(y\)-अवरोध ज्ञात करने के लिए \(x=0\) रखें।
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