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If the line (y=mx+c) cuts the (y)-axis at ((0,7)), what is (c)?यदि रेखा (y=mx+c) (y)-अक्ष को ((0,7)) पर काटती है, तो (c) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(7\)\(7\)
In the form \(y=mx+c\), \(c\) is the y-intercept, the y-coordinate where the line meets the y-axis. The given point is \((0,7)\), so \(c=7\). It would be \(-7\) only if the intercept were \((0,-7)\). Exam tip: every point on the y-axis has \(x=0\).रेखा के रूप \(y=mx+c\) में \(c\), \(y\)-अवरोध होता है, अर्थात वह \(y\)-मान जहाँ रेखा \(y\)-अक्ष को काटती है। दिया गया बिंदु \((0,7)\) है, इसलिए \(c=7\)। \(-7\) तब होता, यदि काटने का बिंदु \((0,-7)\) होता। परीक्षा टिप: \(y\)-अक्ष पर हमेशा \(x=0\) होता है।
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