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In this Class 12 Physics topic from Chapter 1, Electric Charges and Fields, students learn how electric flux is related to the net charge enclosed by a closed surface through Gauss’s law. The topic develops the idea of Gaussian surfaces, uses symmetry to simplify electric-field calculations, and applies the law to charged spherical shells, uniformly charged spheres, infinite line charges, and plane sheets. It also helps students understand the electric field inside conductors and choose suitable surfaces for solving electrostatic problems.
TOPIC PRACTICE
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Hard · Level 5View options
Negative
Positive
Always zero
Infinite
Hard · Level 5View options
Zero
Maximum
Positive
Negative
Hard · Level 5View options
No tangential field remains at the surface in equilibrium
Conductors have no free charge
Outside field is always zero
Conductor is always uncharged
Hard · Level 5View options
Both behave outside like total charge at the centre
Both have zero outside field
Both have distance-independent outside field
Both give circular outside field
Hard · Level 5View options
In conductor field is zero inside, in solid non-conductor it can increase from centre
Both have same nonzero inside field
Both have maximum field at centre
Inside non-conductor field is always zero
Hard · Level 5View options
Zero
Positive
Negative
Equal to sum of outside charges
Hard · Level 5View options
More lines leave than enter
More lines enter than leave
No lines exist
Lines are closed only on surface
Hard · Level 5View options
Field lines are net entering the surface
Field lines are net leaving the surface
Net positive charge is inside
Gauss's law is not valid
Hard · Level 5View options
Lines both enter and leave the surface
External charge creates no field
Gaussian surface has zero area
Field exists only inside
Hard · Level 5View options
When the new surface also uses the same symmetry correctly
When the new surface is open
When enclosed charge changes
When surface colour changes
Hard · Level 5View options
Flux calculation becomes simple
Enclosed charge becomes zero
Electric field disappears
Surface becomes open
Hard · Level 5View options
Zero
Positive
Negative
Equal to area
Hard · Level 5View options
Both are zero
Both are positive
Flux positive and charge zero
Flux zero and charge positive
Hard · Level 5View options
Negative
Positive
Zero
Depends on distance between charges
Hard · Level 5View options
Positive
Negative
Zero
Always infinite
Hard · Level 5View options
Charges placed outside the closed surface
Net charge inside the closed surface
Sign of enclosed charge
Magnitude of enclosed charge
Hard · Level 5View options
Identify the closed surface and its net enclosed charge
Directly write electric field value
Add all outside charges
Always assume spherical surface
Hard · Level 5View options
Net enclosed charge is zero, field need not be zero everywhere
Field is zero everywhere on the surface
No charge can exist outside
Gauss's law will not apply
Hard · Level 5View options
It remains unchanged
It becomes one-ninth
It becomes three times
It becomes nine times
Hard · Level 5View options
One-ninth of the earlier value
One-third of the earlier value
Three times the earlier value
Unchanged
Hard · Level 5View options
Because field decreases but surface area increases and enclosed charge is same
Because electric field actually does not decrease
Because sphere is an open surface
Because Gauss's law is true only for small radius
Hard · Level 5View options
Positive, depending only on the inside charge
Zero, because both charges are equal
Negative, depending on outside charge
Depends on the shape of surface
Hard · Level 5View options
Net enclosed charge is negative
Net enclosed charge is positive
Net enclosed charge is zero
There is no positive charge outside the surface
Hard · Level 5View options
Positive
Negative
Zero
Cannot be determined
Hard · Level 5View options
Negative
Positive
Zero
Always maximum
Question 1HardLevel 5
A part of a Gaussian surface has electric field opposite to the outward normal. What is the flux through that part?
Correct answer: A
Step 1: For a closed surface, outward normal is taken positive. Step 2: If field is opposite to it, field lines are entering. Step 3: Therefore flux through that part is negative.
On a surface, electric field has only tangential component and no normal component. What is the flux through that surface?
Correct answer: A
Step 1: Only the normal component crossing the surface contributes to flux. Step 2: Tangential component runs along the surface and does not pass through it. Step 3: Therefore flux is zero.
Just outside a conductor, field is normal to the surface. Which conductor property does this support along with Gauss's law?
Correct answer: A
Step 1: In electrostatic equilibrium, free charges in a conductor should not move. Step 2: A tangential field would make them move. Step 3: Therefore outside field at the surface remains normal.
What is common between outside field of a uniformly charged conducting sphere and a uniformly charged non-conducting solid sphere?
Correct answer: A
Step 1: In both cases, an outside Gaussian surface encloses the whole charge. Step 2: Due to spherical symmetry, outside result is like a point charge at the centre. Step 3: The main difference appears inside the sphere.
What is the main difference between inside field of a conducting sphere and a uniformly charged solid non-conducting sphere?
Correct answer: A
Step 1: In a conductor, charge stays on surface and field inside is zero. Step 2: In a uniformly charged solid non-conductor, charge is spread through volume. Step 3: Hence inside field can increase from the centre.
A Gaussian surface encloses no charge but external charges create field on it. What is the net flux?
Correct answer: A
Step 1: In Gauss's law, net flux is decided by enclosed net charge. Step 2: The enclosed charge is zero. Step 3: Lines from outside charges enter and leave equally, so net flux is zero.
If net flux through a closed surface is positive, what can be said in terms of field lines?
Correct answer: A
Step 1: Outward direction is taken positive. Step 2: Positive net flux means outgoing contribution is greater. Step 3: This indicates positive net charge inside the closed surface.
If net flux through a closed surface is negative, which explanation is correct?
Correct answer: A
Step 1: For a closed surface, outward direction is positive. Step 2: Negative flux means inward contribution is greater. Step 3: This indicates negative net charge inside.
A point charge is outside a Gaussian surface. It creates field on the surface, yet why is net flux zero?
Correct answer: A
Step 1: Field lines of an external charge can cross the closed surface. Step 2: Lines that enter also leave it. Step 3: Therefore entry and exit cancel and net flux is zero.
When can changing the Gaussian surface still give the same electric field result?
Correct answer: A
Step 1: Gaussian surface is a calculation tool. Step 2: If another surface also captures the symmetry correctly, the same physical field is obtained. Step 3: While changing surface, do not disturb enclosed charge and symmetry logic.
For a symmetric charge distribution, a Gaussian surface is chosen so that field is normal to the surface. What is the advantage?
Correct answer: A
Step 1: For normal field, the full crossing component contributes. Step 2: If magnitude is also simple, total flux is easy to calculate. Step 3: This is why a proper Gaussian surface is chosen.
If a part of a Gaussian surface has zero electric field, what is the flux through that part?
Correct answer: A
Step 1: Flux is related to electric field and area. Step 2: If field itself is zero, no electric effect crosses the surface. Step 3: Therefore flux through that part is zero.
A complete electric dipole is enclosed by a closed surface. What is the relation between net flux and enclosed net charge?
Correct answer: A
Step 1: A dipole has equal positive and negative charges. Step 2: When the whole dipole is enclosed, net enclosed charge is zero. Step 3: By Gauss's law, net flux is also zero.
If a closed surface encloses only the negative charge of a dipole and the positive charge is outside, what is the net flux?
Correct answer: A
Step 1: In Gauss's law, only the charge inside is counted. Step 2: The surface encloses negative charge while positive charge is outside. Step 3: Therefore net flux is negative.
If a closed surface encloses only the positive charge of a dipole and the negative charge is outside, what is the net flux?
Correct answer: A
Step 1: Net flux through a closed surface is decided by net charge inside. Step 2: Only positive charge is inside, so enclosed net charge is positive. Step 3: Hence net flux is positive.
According to Gauss's law, total flux does not depend on which factor?
Correct answer: A
Step 1: Enclosed net charge is the main factor for net flux. Step 2: Outside charges can change field on the surface but not total flux. Step 3: Do not add outside charges to enclosed charge.
In a difficult Gauss's law question, what is the safest first step?
Correct answer: A
Step 1: Gauss's law connects net flux with enclosed charge. Step 2: So first identify the closed surface and which charges are inside it. Step 3: Then use symmetry and calculate field if possible.
In Gauss's law, total flux through a closed surface is zero, but electric field is non-zero at many points on the surface. What is the most correct meaning?
Correct answer: A
Step 1: Gauss's law relates total flux only to net enclosed charge. Step 2: When net charge is zero, positive and negative flux contributions may cancel. Step 3: Do not confuse zero total flux with zero field everywhere.
A Gaussian sphere centered on a point charge has its radius made three times. What happens to total flux?
Correct answer: A
Step 1: Total flux depends on enclosed charge. Step 2: Changing radius still keeps the same point charge enclosed. Step 3: Therefore total flux does not change, although field on the surface changes.
For the same point charge, if the radius of the Gaussian sphere is made three times, what happens to the electric field magnitude on the surface?
Correct answer: A
Step 1: Field of a point charge varies inversely with square of distance. Step 2: Tripling radius makes square of distance nine times. Step 3: Hence field on the surface becomes one-ninth.
When radius of a Gaussian sphere is tripled, field decreases. Why does total flux still remain same?
Correct answer: A
Step 1: Field due to a point charge decreases with distance. Step 2: At the same time, area of the sphere increases with square of distance. Step 3: These effects keep total flux fixed according to enclosed charge.
A positive charge is inside a closed surface and an equal negative charge is outside. What is the total outward flux?
Correct answer: A
Step 1: In Gauss's law, only enclosed charge decides total flux. Step 2: The outside negative charge may create field on the surface, but its net flux contribution is zero. Step 3: Hence total outward flux remains positive.
If total outward flux through a closed surface is negative, which conclusion about net enclosed charge is correct?
Correct answer: A
Step 1: The sign of outward flux is linked to the sign of net enclosed charge. Step 2: Negative total flux means net field lines are inward. Step 3: Therefore net enclosed charge is negative.
A closed surface encloses three positive charges and two negative charges of equal magnitude. What is the sign of total flux?
Correct answer: A
Step 1: Total flux depends on net enclosed charge. Step 2: Three positive and two equal negative charges leave one positive charge as net. Step 3: Therefore total outward flux is positive.
A closed surface encloses two positive charges and five negative charges of equal magnitude. What will be the total flux?
Correct answer: A
Step 1: In Gauss's law, the sign of net enclosed charge gives the sign of total flux. Step 2: Two positive and five negative charges give net negative charge. Step 3: Hence total outward flux is negative.
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