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In this Class 12 Physics topic from Chapter 1, Electric Charges and Fields, students learn how electric flux is related to the net charge enclosed by a closed surface through Gauss’s law. The topic develops the idea of Gaussian surfaces, uses symmetry to simplify electric-field calculations, and applies the law to charged spherical shells, uniformly charged spheres, infinite line charges, and plane sheets. It also helps students understand the electric field inside conductors and choose suitable surfaces for solving electrostatic problems.
TOPIC PRACTICE
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Expert · Level 4View options
Positive charge is a source of field lines
Positive charge is an end point of field lines
Gaussian surface is open
Field exists only on one side
Expert · Level 4View options
Toward the sheet
Away from the sheet
Parallel to the surface
Circular
Expert · Level 4View options
Radially outward from the wire
Radially inward toward the wire
Along the wire
Circular
Expert · Level 4View options
Lack of symmetry makes it difficult to separate field from flux
Net flux is not defined for irregular distributions
Gauss's law applies only to conductors
Unit of charge changes in irregular distributions
Expert · Level 4View options
Three times
Nine times
Same
One third
Expert · Level 4View options
Negative
Positive
Zero
Depends on surface shape
Expert · Level 4View options
Net charge inside is zero
Field is zero everywhere on surface
No outside charge exists
Surface is open
Expert · Level 4View options
It remains same
It increases
It decreases
Its sign changes
Expert · Level 4View options
Negative
Positive
Zero
Infinite
Expert · Level 4View options
Zero
Maximum
Positive
Negative
Expert · Level 4View options
Tangential field would move free charges
Conductors have no free charges
Outside field is always zero
A conductor always remains uncharged
Expert · Level 4View options
Both behave like total charge placed at the centre
Both have zero outside field
Both have distance-independent outside field
Both give circular outside field
Expert · Level 4View options
In conductor field is zero, in solid non-conductor it can increase from centre
In both field is same and nonzero
In both field is maximum at centre
In solid non-conductor field is always zero
Expert · Level 4View options
Zero
Positive
Negative
Depends on sum of outside charges
Expert · Level 4View options
More lines leave than enter
More lines enter than leave
No field line exists
Lines form closed loops
Expert · Level 4View options
Field lines are net entering the surface
Field lines are net leaving the surface
Net positive charge is inside
Gauss's law is not applicable
Expert · Level 4View options
Lines that enter also leave
External charge creates no field
Gaussian surface has zero area
Field exists only inside the surface
Expert · Level 4View options
When the new surface preserves symmetry and enclosed charge correctly
When the new surface is open
When enclosed charge changes
When outside charges are counted as inside
Expert · Level 4View options
Flux calculation becomes simple
Enclosed charge becomes zero
Electric field disappears
Gauss's law changes
Expert · Level 4View options
Zero
Positive
Negative
Equal to area
Expert · Level 4View options
Both are zero
Both are positive
Charge is zero and flux is positive
Charge is positive and flux is zero
Expert · Level 4View options
Negative
Positive
Zero
Depends on distance between charges
Expert · Level 4View options
Positive
Negative
Zero
Always infinite
Expert · Level 4View options
Charges placed outside the closed surface
Net charge inside the closed surface
Sign of enclosed charge
Magnitude of enclosed charge
Expert · Level 4View options
Identify the closed surface and its net enclosed charge
Directly write the electric field formula
Add all outside charges
Always assume a spherical surface
Question 1ExpertLevel 4
Why is the field on both sides of a positively charged infinite plane sheet directed outward?
Correct answer: A
Step 1: Field lines emerge from positive charge. Step 2: Symmetry of an infinite sheet is same on both sides. Step 3: Hence field points away from the sheet on both sides.
For a negatively charged infinite plane sheet, where will the electric field point on both sides?
Correct answer: A
Step 1: Field lines go toward negative charge. Step 2: Symmetry of an infinite sheet is same on both sides. Step 3: Therefore field points toward the sheet on both sides.
For a long positive line charge, what is the direction of electric field around it?
Correct answer: A
Step 1: Field lines emerge from a positive line charge. Step 2: Cylindrical symmetry makes the direction radial and perpendicular to the wire. Step 3: For positive wire, remember outward direction.
Gauss's law is always true, yet why can it become a weak tool for finding field in irregular charge distributions?
Correct answer: A
Step 1: Gauss's law gives correct total flux. Step 2: To find field, simple behaviour of field on the surface is needed. Step 3: In irregular distributions, this simplicity is absent.
If net charge inside a Gaussian surface becomes three times and surface area also becomes three times, what happens to total flux?
Correct answer: A
Step 1: Net flux is proportional to enclosed net charge. Step 2: Surface area does not independently decide net flux. Step 3: Since enclosed charge is tripled, net flux becomes three times.
A closed surface encloses positive two coulomb and negative five coulomb charges. What is the sign of total flux?
Correct answer: A
Step 1: Add the charges enclosed by the closed surface. Step 2: Positive two and negative five give a negative net charge. Step 3: Negative enclosed charge gives negative net flux.
As many field lines leave a closed surface as enter it. What follows from Gauss's law?
Correct answer: A
Step 1: Outgoing lines give positive flux and incoming lines give negative flux. Step 2: If both are equal, net flux is zero. Step 3: Zero net flux means zero enclosed net charge.
Charges outside a closed surface are rearranged but net charge inside remains same. What happens to net flux?
Correct answer: A
Step 1: Net flux depends on enclosed net charge. Step 2: External charges can change field distribution on the surface. Step 3: If enclosed net charge remains same, net flux remains same.
On a part of a Gaussian surface, electric field is opposite to the outward normal. What is the flux through that part?
Correct answer: A
Step 1: For a closed surface, outward normal is taken positive. Step 2: If field is opposite to it, the field is entering that part. Step 3: Therefore flux through that part is negative.
Electric field on a surface has only tangential component. What is the electric flux through that surface?
Correct answer: A
Step 1: Only the normal component crossing the surface contributes to flux. Step 2: Tangential component runs along the surface and does not pass through it. Step 3: Therefore flux is zero.
Electric field just outside a conductor is found normal to the surface. Which physical reason is this linked to?
Correct answer: A
Step 1: Free charges in a conductor can move easily. Step 2: Any field component along the surface would keep them moving. Step 3: Hence in equilibrium, the outside field is normal to the surface.
What is common in the outside electric field of a uniformly charged conducting sphere and a uniformly charged solid non-conducting sphere?
Correct answer: A
Step 1: In both cases, an outside Gaussian surface encloses the whole charge. Step 2: Due to spherical symmetry, outside field is like a point charge. Step 3: The main difference lies in the field inside the sphere.
What is the main difference between inside fields of a conducting sphere and a uniformly charged solid non-conducting sphere?
Correct answer: A
Step 1: In a conductor, excess charge stays on surface and inside field is zero. Step 2: In a solid non-conductor, charge is spread through volume. Step 3: Therefore field inside the non-conductor can increase outward from centre.
A Gaussian surface encloses no charge, but external charges create field on the surface. What is the net flux?
Correct answer: A
Step 1: Net flux is decided by enclosed net charge. Step 2: No charge is enclosed, so enclosed charge is zero. Step 3: External lines enter and leave equally, so net flux is zero.
The net flux through a closed surface is positive. What is its correct meaning in terms of field lines?
Correct answer: A
Step 1: For a closed surface, outward direction is taken positive. Step 2: Positive net flux means outgoing contribution is greater. Step 3: It indicates positive net charge inside.
The net flux through a closed surface is negative. Which explanation is correct?
Correct answer: A
Step 1: For a closed surface, outward direction is positive. Step 2: Negative net flux means inward contribution is greater. Step 3: This indicates negative net charge inside.
A point charge is outside a Gaussian surface. It creates field on the surface, yet why is net flux zero?
Correct answer: A
Step 1: Field lines from an outside charge can cross the closed surface. Step 2: As many lines enter as leave. Step 3: Entry and exit cancel, giving zero net flux.
When can changing the Gaussian surface still give the same electric field result?
Correct answer: A
Step 1: Gaussian surface is a calculation tool, not necessarily a physical object. Step 2: If the new surface uses symmetry correctly, the result can remain same. Step 3: Do not spoil enclosed charge and field simplicity.
For a symmetric charge distribution, why is a Gaussian surface chosen where field is normal to the surface?
Correct answer: A
Step 1: For normal field, the full field component crosses the surface. Step 2: If magnitude is also simple, total flux is easy to find. Step 3: This is the aim of choosing a proper Gaussian surface.
Electric field is zero on a part of a Gaussian surface. What is the flux through that part?
Correct answer: A
Step 1: Flux comes from relation between electric field and area. Step 2: If electric field itself is zero, no field crosses the surface. Step 3: Therefore flux through that part is zero.
A complete electric dipole is enclosed by a closed surface. Which statement about enclosed net charge and net flux is correct?
Correct answer: A
Step 1: A dipole has equal positive and negative charges. Step 2: If the whole dipole is inside, enclosed net charge is zero. Step 3: By Gauss's law, net flux is also zero.
If a closed surface encloses only the negative charge of a dipole and the positive charge is outside, what is the net flux?
Correct answer: A
Step 1: In Gauss's law, only charge inside the surface is counted. Step 2: Negative charge is inside and positive charge is outside. Step 3: Therefore enclosed net charge and net flux are negative.
If a closed surface encloses only the positive charge of a dipole and the negative charge is outside, what is the net flux?
Correct answer: A
Step 1: Net flux through a closed surface is decided by net enclosed charge. Step 2: Only positive charge is inside, so enclosed charge is positive. Step 3: Hence net flux is positive.
According to Gauss's law, total flux does not depend on which factor?
Correct answer: A
Step 1: Net flux is based on enclosed net charge. Step 2: Outside charges can change local field on the surface. Step 3: But they do not change net flux, so do not add them to enclosed charge.
In a difficult Gauss's law question, what should be the safest first step?
Correct answer: A
Step 1: Gauss's law relates net flux to enclosed charge. Step 2: So first identify the closed surface and which charges are inside. Step 3: Then use symmetry to choose surface and calculate field.
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