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In this Class 12 Physics topic from Chapter 1, Electric Charges and Fields, students learn how electric flux is related to the net charge enclosed by a closed surface through Gauss’s law. The topic develops the idea of Gaussian surfaces, uses symmetry to simplify electric-field calculations, and applies the law to charged spherical shells, uniformly charged spheres, infinite line charges, and plane sheets. It also helps students understand the electric field inside conductors and choose suitable surfaces for solving electrostatic problems.
TOPIC PRACTICE
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Expert · Level 2View options
Because an oblique field has a tangential component that would move charges
Because field never exists outside a conductor
Because charge cannot stay on a conductor
Because Gauss's law does not apply to closed surfaces
Expert · Level 2View options
Because electric field inside conductor material is zero in electrostatic condition
Because a Gaussian surface is always open
Because a conductor never has charge
Because outside field is zero
Expert · Level 2View options
Because excess charge inside would not allow zero electric field inside
Because surface area is zero
Because conductors have no free charges
Because Gauss's law does not apply to surfaces
Expert · Level 2View options
Zero
Infinite
Same as external field
Parallel to surface
Expert · Level 2View options
Zero
Maximum in positive direction
Equal to cavity charge
Infinite
Expert · Level 2View options
Equal magnitude negative charge
Equal magnitude positive charge
Zero
Double positive charge
Expert · Level 2View options
Because outside field is directly related to surface charge density
Because field inside conductor is larger there
Because charge is zero there
Because the surface becomes open
Expert · Level 2View options
Zero
Negative
Positive
Cannot be determined
Expert · Level 2View options
Positive
Negative
Zero
Depends on surface shape
Expert · Level 2View options
Such field gives positive total flux, inconsistent with zero net enclosed charge
Outward field always gives negative flux
Zero charge always gives outward field
Gauss's law applies only to spheres
Expert · Level 2View options
Because the idea of enclosed charge is clear only for a closed surface
Because field does not exist on an open surface
Because area of an open surface is zero
Because external charge is always zero
Expert · Level 2View options
Maximum
Positive
Zero
Negative
Expert · Level 2View options
Both statements cannot be true together
External charge always makes total flux positive
Zero charge always creates positive flux
Gauss's law applies only to negative charge
Expert · Level 2View options
It becomes difficult to treat field as uniform on the Gaussian surface
The idea of total flux disappears
Gauss's law becomes false
Charge ceases to exist
Expert · Level 2View options
No, total flux is determined by net enclosed charge
Yes, the external negative charge always cancels it
Yes, if the external charge is very large
It depends on surface shape
Expert · Level 2View options
One fourth
Half
Double
Unchanged
Expert · Level 2View options
One fourth
Half
Double
Unchanged
Expert · Level 2View options
Half
One fourth
Unchanged
Double
Expert · Level 2View options
Point charge distance independent, line charge inverse square, sheet inverse distance
Point charge inverse square, line charge inverse distance, infinite sheet distance independent
All three distance independent
All three inverse square
Expert · Level 2View options
Double
Half
Zero
Unchanged
Expert · Level 2View options
Positive
Negative
Zero
Depends on external charge
Expert · Level 2View options
Because one face can be outside in field and the other inside the conductor where field is zero
Because it makes an open surface
Because it destroys charge
Because field is always parallel in the pillbox
Expert · Level 2View options
Yes, it is always correct
No, positive and negative local flux may cancel
Yes, only on a closed surface
No, because net charge is always positive
Expert · Level 2View options
No, unless symmetry makes the field simple
Yes, field at every point is always obtained
Yes, only due to external charges
No, Gauss's law does not give flux
Expert · Level 2View options
Whether surface is closed, what net charge is enclosed, and whether symmetry is useful
Surface colour, temperature, and mass
Only external charge, surface name, and beauty of diagram
First assume field is same everywhere
Question 1ExpertLevel 2
Electric field just outside a charged conductor is shown oblique. Why is this inconsistent in electrostatic condition?
Correct answer: A
Step 1: In an electrostatic conductor, free charges on the surface are at rest. Step 2: A tangential component of an oblique field would move them. Step 3: Therefore the field outside must be perpendicular to the surface.
Why does a closed Gaussian surface drawn inside a conductor enclose zero net charge?
Correct answer: A
Step 1: Inside conductor material in electrostatic condition, electric field is zero. Step 2: Therefore total flux through an internal closed surface is zero. Step 3: By Gauss's law, net charge enclosed by that surface must be zero.
Why does excess charge on a charged conductor reside on the surface?
Correct answer: A
Step 1: Electric field inside an electrostatic conductor must be zero. Step 2: If excess net charge were inside, Gauss's law would give non-zero flux. Step 3: Hence excess charge arranges itself on the surface.
A conductor has an empty cavity with no charge inside it. In electrostatic condition, what is the electric field inside the cavity?
Correct answer: A
Step 1: Electric field inside conductor material is zero. Step 2: An empty cavity has no internal charge to start or end field lines. Step 3: In electrostatic condition, the conductor shields the cavity, so field inside it is zero.
A positive charge is placed inside a cavity of a conductor. What will be the electric field inside the conductor material?
Correct answer: A
Step 1: Even with a charge in the cavity, conductor material maintains zero field in electrostatic condition. Step 2: Induced charges on surfaces arrange to ensure this. Step 3: Therefore electric field inside conductor material remains zero.
A positive charge is placed inside a conductor cavity. What will be the total induced charge on the inner surface of the cavity?
Correct answer: A
Step 1: Electric field inside conductor material must be zero. Step 2: A Gaussian surface in conductor material around the cavity has zero flux. Step 3: Hence induced charge on the inner surface must be equal and opposite to the positive charge in the cavity.
Why is electric field just outside a conductor stronger where surface charge density is higher?
Correct answer: A
Step 1: Field just outside a conductor surface depends on surface charge density. Step 2: Denser charge gives denser field lines. Step 3: Therefore field can be stronger near sharp parts.
On a closed surface, electric field is outward everywhere and non-zero. What is the sign of net enclosed charge?
Correct answer: C
Step 1: Outward field gives positive flux through a closed surface. Step 2: Non-zero outward field everywhere gives positive total flux. Step 3: By Gauss's law, net enclosed charge is positive.
On a closed surface, electric field is inward everywhere. What is the sign of net enclosed charge?
Correct answer: B
Step 1: Area vector of a closed surface is outward. Step 2: Inward field is opposite to the area vector. Step 3: Total flux is negative, so net enclosed charge is negative.
If net enclosed charge is zero but field is said to be outward everywhere on a closed surface, what is the issue?
Correct answer: A
Step 1: If net enclosed charge is zero, total flux must be zero. Step 2: If field is outward everywhere, every part gives positive contribution. Step 3: That gives positive total flux, so the statement is inconsistent.
If a Gaussian surface is not closed, why is direct use of Gauss's law wrong?
Correct answer: A
Step 1: Gauss's law relates total flux to a closed surface. Step 2: For an open surface, inside and outside are not clearly defined. Step 3: Therefore the Gaussian surface must be closed.
If electric field is parallel to a Gaussian surface everywhere, what is the total flux?
Correct answer: C
Step 1: Flux comes from the component of field crossing the surface. Step 2: A parallel field does not pass through the surface. Step 3: Hence flux through every part and total flux are zero.
Total flux through a closed surface is positive, but net enclosed charge is stated to be zero. What is the correct comment?
Correct answer: A
Step 1: In Gauss's law, total flux is proportional to net enclosed charge. Step 2: If net enclosed charge is zero, total flux must be zero. Step 3: Hence positive flux and zero enclosed charge are inconsistent.
While finding field using Gauss's law, what difficulty arises when symmetry is lacking?
Correct answer: A
Step 1: Gauss's law remains true even without symmetry. Step 2: But to find field, flux must be written in a simple form. Step 3: Without symmetry, field is not uniform or simply directed on the surface.
A closed surface contains net positive charge. Can total flux be made zero by placing an external negative charge nearby?
Correct answer: A
Step 1: External charge can change field direction and magnitude on the surface. Step 2: But in Gauss's law total flux is determined by net enclosed charge. Step 3: If enclosed charge is positive, total flux remains positive.
Outside a uniformly charged conducting sphere, what happens to electric field when distance from the centre is doubled?
Correct answer: A
Step 1: Outside a conducting sphere, field behaves like that of a point charge at the centre. Step 2: Point charge field decreases inversely as square of distance. Step 3: Doubling distance makes field one fourth.
For a long charged line, what happens to electric field when distance from the line is doubled?
Correct answer: B
Step 1: Field of a long line charge is inversely proportional to distance. Step 2: Doubling distance halves the field. Step 3: Do not confuse it with inverse square relation of point charge.
For an infinite charged plane sheet, what happens to electric field when distance from the sheet is doubled?
Correct answer: C
Step 1: For an infinite plane sheet, Gauss's law gives field independent of distance. Step 2: Doubling distance does not change the field in the ideal infinite sheet case. Step 3: This result depends on infinite sheet symmetry.
Which order of distance dependence is correct for three results derived using Gauss's law?
Correct answer: B
Step 1: For a point charge, spherical area grows as square of distance. Step 2: For a line charge, cylindrical curved area grows with distance. Step 3: For an infinite sheet, field is independent of distance.
If a closed surface has uniform electric field everywhere perpendicular outward and total area is doubled while field remains same, what happens to total flux?
Correct answer: A
Step 1: In this special case, total flux equals field times total area. Step 2: Field is unchanged and area is doubled. Step 3: Therefore total flux doubles, meaning enclosed charge must also be doubled.
If a closed surface has uniform magnitude field everywhere perpendicular inward, what is the sign of net enclosed charge?
Correct answer: B
Step 1: Area vectors of a closed surface point outward. Step 2: Inward field is opposite to them. Step 3: Hence total flux is negative and net enclosed charge is negative.
Why is a small pillbox useful for finding field near the outer surface of a charged conductor using Gauss's law?
Correct answer: A
Step 1: Inside a conductor in electrostatic condition, electric field is zero. Step 2: A small pillbox can be chosen crossing the surface. Step 3: This gives a simple relation between flux through the outer face and surface charge density.
If total flux through a surface is zero, is it correct to assume electric field is zero everywhere while finding the field?
Correct answer: B
Step 1: Total flux is an algebraic sum. Step 2: Contributions from different parts may cancel even when local field is non-zero. Step 3: Therefore zero total flux does not mean field is zero everywhere.
Total flux through a closed surface is known from Gauss's law. Does this always give electric field at every point on the surface?
Correct answer: A
Step 1: Gauss's law gives total flux. Step 2: Total flux is a surface sum, not field at one point. Step 3: Strong symmetry is needed to extract the electric field simply.
In an expert-level Gauss's law question, which three things should be checked first?
Correct answer: A
Step 1: Gauss's law for total flux requires a closed surface. Step 2: Total flux is determined by net enclosed charge. Step 3: To find field, symmetry is needed, so check these three things first.
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