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In this Class 12 Physics topic from Chapter 1, Electric Charges and Fields, students learn the basic nature of electric charge and the law of conservation of charge. They understand that charge can neither be created nor destroyed, but may be transferred between bodies through processes such as rubbing, contact, or induction. The topic also builds a foundation for analysing charged systems and applying charge conservation while studying electric fields and related phenomena.
TOPIC PRACTICE
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Hard · Level 1View options
In the cavity, \(E=0\) and \(V\) is necessarily zero everywhere.
In the cavity, \(E\) is non-zero, but \(V\) is constant everywhere.
In the cavity, \(E=0\) and \(V\) is the same everywhere, but its value is not necessarily zero.
\(E=0\) only at the centre of the cavity; at other points \(E\) is non-zero and \(V\) varies.
Hard · Level 1View options
Zero
Equal-magnitude positive charge \(+q\)
Negative charge of half the magnitude \(-q/2\)
Equal-magnitude negative charge \(-q\)
Hard · Level 1View options
In an insulator, free charges move throughout the material to make the internal electric field zero, whereas only dipoles align in a conductor.
In an insulator, bound positive and negative charges undergo a small relative displacement or permanent dipoles align, whereas free charges redistribute in a conductor.
Polarisation in an insulator requires a net transfer of charge into the material, whereas induction changes the total charge of an isolated conductor.
In both an insulator and a conductor, only a small displacement of charges within molecules occurs; free charges do not redistribute in either case.
Hard · Level 1View options
The desired charge may not be retained
The mass of the conductor will increase
Charge will convert into mass
The conductor will become a permanent insulator
Hard · Level 1View options
In charge separation the net charge may change, but in actual charging it does not
In charge separation the net charge generally does not change, whereas in actual charging the net charge changes
No local effect is produced in either process
Both processes occur only in insulators
Hard · Level 1View options
\(\dfrac{|\sigma|}{\varepsilon_0}\)
\(\dfrac{|\sigma|}{2\varepsilon_0}\)
\(\dfrac{\varepsilon_0}{|\sigma|}\)
\(\dfrac{|\sigma|}{4\pi\varepsilon_0}\)
Hard · Level 1View options
\(+q\)
\(-q\)
\(0\)
\(+2q\)
Hard · Level 1View options
Because the metal completely converts the energy of the external electric field into heat.
Because free charges redistribute on the outer surface and produce an induced field that cancels the external field in the empty interior.
Because electric field lines terminate on a neutral metal, so no field can reach its interior.
Because electrons flow continuously and maintain a field opposite to the external field in the interior.
Hard · Level 1View options
When the net charge on the conductor becomes zero
When the electric field inside the conductor becomes zero and the conductor becomes equipotential
When the electric field inside the conductor becomes uniform but non-zero
When the surface charge density becomes the same over the entire conductor
Hard · Level 1View options
The attraction of induced negative bound charge on the nearer side of the sphere is greater than the repulsion of induced positive bound charge on the farther side.
The forces on the induced negative and positive bound charges are equal, so the sphere is attracted.
The positive point charge makes the sphere negative by causing a flow of free electrons through the insulator.
Due to polarisation, the sphere acquires a net positive charge and is attracted towards the positive point charge.
Hard · Level 1View options
Because the electric field inside a conductor is zero.
Because any tangential component of the electric field would keep moving free charges along the surface, so charges redistribute until that component becomes zero.
Because the surface charge density is uniform on every conductor.
Because a conductor’s surface is always spherical and the field is radial.
Hard · Level 1View options
Negative charge (electrons)
Positive charge
Equal amounts of positive and negative charge
No charge flows because the conductor is initially neutral
Hard · Level 1View options
Polarisation
Perfect conduction
Earthing
Destruction of charge
Hard · Level 1View options
The electric field inside the conducting material is zero.
The electric field outside the conductor is zero.
The net charge on the conductor is zero.
The potential at every point of the conductor is zero.
Hard · Level 1View options
An isolated spherical conductor kept away from external influences
A spherical conductor placed near a point charge
An irregularly shaped conductor kept away from external influences
An isolated conductor with a sharp projection
Hard · Level 1View options
The external electric field redistributes the conductor’s free charges by induction, while its total charge remains unchanged.
The external charge changes the conductor’s total charge without contact.
For a conductor to be equipotential, its surface charge density must be uniform everywhere.
Surface charge density depends only on the conductor’s radius, not on external charges.
Hard · Level 1View options
They will redistribute along the surface until the tangential electric field becomes zero.
They will redistribute until the normal component of electric field at the surface becomes zero.
They will remain stationary because a conductor surface is always equipotential.
They will move into the conductor until every component of electric field at the surface becomes zero.
Hard · Level 1View options
When it is isolated on a dry insulating stand
When it is held in a hand
When it is connected to Earth by a metal wire
When it is placed directly on a damp floor
Hard · Level 1View options
When both conductors attain the same electric potential
When both conductors acquire equal total charge
When both conductors acquire equal surface charge density
When the electric field around both conductors becomes zero
Hard · Level 1View options
No, the conductor may have net excess charge on its outer surface.
Yes, a zero internal electric field means that the conductor is electrically neutral.
No, excess charge remains uniformly distributed throughout the volume of the conductor.
Yes, a zero internal electric field means that charge has been destroyed.
Hard · Level 1View options
Charge can flow between the conductor and Earth, while Earth’s enormous capacitance makes the change in its potential negligible.
As soon as it is connected to Earth, the conductor’s charge always becomes zero without any flow of charge.
Earth keeps the conductor’s total charge unchanged but makes the electric field outside the conductor zero.
On connecting to Earth, the potentials of both the conductor and Earth undergo equal and appreciable changes.
Hard · Level 1View options
\(-q,\; Q+q\)
\(+q,\; Q-q\)
\(-q,\; Q-q\)
\(0,\; Q\)
Hard · Level 1View options
Because sharing depends on final equilibrium and size
Because conservation becomes wrong
Because total charge becomes zero in both
Because electrons are destroyed
Hard · Level 1View options
Define the system boundary and find total initial charge
Add all magnitudes without signs
Assume only final charge
Ignore all electrons
Hard · Level 1View options
Because electrons can move back to earth
Because protons are destroyed
Because the conductor melts
Because charge quantization breaks
Question 1HardLevel 1
A closed hollow conductor is in electrostatic equilibrium. Its cavity is empty, and a stationary point charge is placed outside the conductor. Which statement about the electric field \(E\) and electric potential \(V\) inside the cavity is correct?
Correct answer: C
In electrostatic equilibrium, the conductor and the inner surface of its cavity are equipotential. Since the closed cavity contains no charge, the unique electrostatic solution for a boundary at constant potential is a constant potential throughout the cavity. Therefore, \(\mathbf{E}=-\nabla V=0\) everywhere. The external charge may change the constant value of the conductor's potential, so that value need not be zero. Option A is incorrect because it assumes that the potential must be zero.
In electrostatic equilibrium, if a positive point charge \(+q\) is placed inside a closed cavity of a conductor, what is the total induced charge on the inner surface of the cavity?
Correct answer: D
In electrostatic equilibrium, the electric field within the conducting material is zero. Consider a Gaussian surface lying entirely in the conductor and enclosing the cavity. The electric flux through this surface is zero, so Gauss's law requires the net enclosed charge to be zero. Therefore, the charge \(+q\) inside the cavity induces a total charge \(-q\) on the inner surface. The induced charge may be distributed non-uniformly, but its total is always \(-q\), not \(-q/2\).
When a neutral, isolated material is placed in an external electrostatic field, what is the main microscopic difference between polarisation in an insulator and electrostatic induction in a conductor?
Correct answer: B
In an insulator, charges are normally bound to atoms or molecules. An external field can slightly separate the positive and negative charge centres or align permanent molecular dipoles. In contrast, free electrons or other free charges redistribute through a conductor; at electrostatic equilibrium, the electric field inside the conductor is zero. Unlike option C, polarisation or induction alone does not change the net charge of an isolated object.
In charging by induction, what problem can occur if the external charged object is removed before removing the earth connection?
Correct answer: A
The governing concept is the required sequence in charging by induction. The nearby charged object separates charges in the conductor, while the earth connection allows charge to enter or leave. If the external object is removed first, the separation disappears while earthing remains, so charge can flow to or from Earth and the intended net charge may be cancelled. Option A is correct; the other choices violate conservation and conductor behaviour.
What is the most correct difference between charge separation only and actual charging?
Correct answer: B
The governing concept is conservation of total charge. In charge separation or induction without contact, positive and negative charges merely redistribute inside the object, so the object’s net charge generally remains unchanged. In actual charging, electrons are transferred to or from another body or Earth, changing the net charge. Option B states this distinction correctly. A reverses it, while C and D deny real charge redistribution or misidentify the materials involved.
A conductor is in electrostatic equilibrium in vacuum and has surface charge density \(\sigma\) at a point on its surface. What is the magnitude of the electric field just outside the surface?
Correct answer: A
In electrostatic equilibrium, the electric field inside a conductor is zero, and the field immediately outside is normal to its surface. Applying Gauss's law to a small pillbox straddling the surface gives \(EA=\sigma A/\varepsilon_0\). Hence, \(E=|\sigma|/\varepsilon_0\). Option B applies to the field on either side of an isolated infinite charged sheet, not to the surface of a conductor.
An isolated conductor is initially neutral. A charge \(+q\) is placed inside its cavity without touching the conductor. In electrostatic equilibrium, what is the total charge on the outer surface of the conductor?
Correct answer: A
The electric field inside the conducting material must be zero. Hence, a total induced charge \(-q\) appears on the inner surface of the cavity. Since the isolated conductor was initially neutral, its total charge remains zero; therefore, the outer surface must carry \(+q\) to balance the \(-q\) on the inner surface. Option \(0\) refers to the net charge of the conductor, not to the charge on its outer surface.
Why does a closed metal cage placed in an external electrostatic field shield its empty interior from the electric field?
Correct answer: B
In electrostatic equilibrium, free charges in a conductor redistribute until the electric field within the conducting material is zero. If the closed conductor has an empty cavity, the external field induces charges on its outer surface. The field produced by these induced charges makes the net electric field in the empty interior zero. Option D is incorrect because, after equilibrium is reached, charges do not flow continuously.
When does the rearrangement of free charges in a conductor stop?
Correct answer: B
At electrostatic equilibrium, the electric field inside a conductor is zero. Therefore, the electric force on a free charge, \(F=qE\), is zero, and no force remains to cause further rearrangement. The conductor consequently has the same potential throughout, so it is equipotential. In option C, a non-zero electric field would still exert a force on free charges. A conductor need not have zero net charge to be in electrostatic equilibrium.
A neutral insulating sphere is placed near a positive point charge. Why does the sphere experience a net attraction without any flow of free charges?
Correct answer: A
The positive point charge slightly displaces bound charges in the atoms or molecules of the insulator; this is polarisation. The nearer side of the sphere becomes relatively negative and the farther side relatively positive, while the sphere remains overall neutral. The attraction on the nearer negative bound charge is stronger because electric force decreases with distance. Hence, it exceeds the repulsion on the farther positive side, producing a net attraction. Option B is incorrect because the forces on the two sides are not equal: their distances from the point charge are different.
Why is the electric field just outside the surface of a conductor perpendicular to the surface in electrostatic equilibrium?
Correct answer: B
In electrostatic equilibrium, the free charges in a conductor are at rest. If the electric field had a component parallel to the surface, it would exert a force on free charges and make them move along the surface. Charges redistribute until the tangential component becomes zero. Thus, just outside the surface only the normal component remains, so the electric field is perpendicular to the surface. Option A states the correct fact that the field inside a conductor is zero, but it does not by itself explain why the field at the surface has no tangential component.
A neutral metal conductor is earthed, and a positively charged rod is brought near it without touching it. Which type of charge flows from the earth into the conductor?
Correct answer: A
The positively charged rod attracts the conductor’s free electrons toward the side nearer the rod. When the conductor is earthed, electrons flow from the earth into the conductor and gather on the side facing the rod. Therefore, negative charge enters the conductor from the earth. In a metal, positive ions are fixed in the lattice, so positive charge does not flow through the conductor as in option B.
When a charged rod is brought near an initially neutral insulator, the insulator is attracted towards the rod but its net charge remains unchanged. What explains this?
Correct answer: A
The electric field of the charged rod slightly displaces or reorients the bound positive and negative charges in the insulator. The induced charge of opposite sign on the nearer side is closer to the rod, so its attraction is stronger than the repulsion due to the like induced charge on the farther side. No charge is transferred to or from the insulator, so its net charge remains zero. This is polarisation, not earthing or destruction of charge.
What is the direct reason that a conductor in electrostatic equilibrium is an equipotential body?
Correct answer: A
In electrostatic equilibrium, free charges redistribute until the electric field inside the conducting material becomes zero. Since \(\mathbf{E}=-\nabla V\), \(\mathbf{E}=0\) means there is no change of potential within the conductor; hence the conductor and its surface are equipotential. Option B is not necessary: the electric field outside a conductor may be nonzero even though the conductor is equipotential.
In electrostatic equilibrium, which conductor will have a uniform charge density over its external surface when kept away from external charges and external electric fields?
Correct answer: A
Because of the rotational symmetry of an isolated spherical conductor, every point on its external surface is equivalent. Hence, in electrostatic equilibrium, charge is distributed uniformly and the surface charge density is \\(sigma=Q/(4\\pi R^2)\\). In contrast, a nearby point charge makes the distribution non-uniform by induction, and irregular or sharp regions generally have greater charge density.
If an external charge is placed near an isolated charged spherical conductor, why can its initially uniform surface charge density become non-uniform?
Correct answer: A
The electric field of the external charge exerts forces on the conductor’s free charges. They redistribute until the conductor reaches electrostatic equilibrium and remains equipotential. The external charge breaks spherical symmetry, so the surface charge density need not remain uniform. This is redistribution by induction; the conductor’s total charge does not change without charge transfer. Option C is incorrect because an equipotential conductor need not have uniform surface charge density.
If a non-zero tangential component of electric field exists at the surface of a conductor, what will free charges tend to do to minimise energy?
Correct answer: A
A tangential electric field exerts a force along the surface on free charges, so they move and redistribute, reducing the electrostatic potential energy of the system. This redistribution continues until electrostatic equilibrium is reached, at which point the tangential component of the electric field at the surface is zero. In contrast, the normal component need not be zero; it can be associated with surface charge density.
Under which condition is a metal object most likely to retain a static charge for the longest time?
Correct answer: A
Charge can redistribute freely in a metal, but it does not disappear by itself. A conducting path to Earth is needed for charge to leak away. A dry insulating stand keeps the metal object isolated from Earth and minimises leakage. In contrast, a hand or an earthing wire provides a conducting path to Earth, while a damp floor can increase leakage because of moisture.
Two isolated conductors initially at different potentials are brought into contact. Until which condition does net charge transfer between them continue?
Correct answer: A
A potential difference between conductors in contact causes net charge transfer. The transfer stops when the connected system reaches electrostatic equilibrium and both conductors are at the same potential. Equal potential does not imply equal total charge; conductors of different size or capacitance can retain different final charges.
In electrostatic equilibrium, if the electric field within the material of a conductor is zero, does it mean that the conductor has no net charge?
Correct answer: A
In electrostatic equilibrium, free charges redistribute until the electric field within the conducting material becomes zero. The conductor can still have net excess charge, which resides on its outer surface. Therefore, a zero internal field does not prove that the conductor is neutral. Option C is incorrect because excess charge does not remain uniformly distributed throughout the conductor’s volume in electrostatic equilibrium.
When a charged conductor is connected to Earth, what is the most appropriate physical reason for calling Earth a huge charge reservoir?
Correct answer: A
Electrons can flow between an earthed conductor and Earth until the conductor reaches Earth’s potential. Earth has an extremely large effective capacitance, so accepting or supplying an ordinary amount of charge produces a practically negligible change in Earth’s potential. Therefore, Earth acts as a huge charge reservoir. Option B is incorrect because charge must actually flow for the conductor’s charge to change, and the conductor’s final charge is not necessarily zero in every situation.
An isolated conductor has an initial net charge \(Q\) and contains a cavity. A positive point charge \(+q\) is held stationary inside the cavity without touching the conductor. At electrostatic equilibrium, what are the charges on the inner and outer surfaces of the conductor, respectively?
Correct answer: A
At electrostatic equilibrium, the electric field inside the conducting material is zero. Hence, a Gaussian surface just within the conductor around the cavity must enclose zero net charge, so the inner surface acquires an induced charge \(-q\). Because the isolated conductor initially had total charge \(Q\), its total charge must remain \(Q\). Therefore, the outer surface must carry \(Q-(-q)=Q+q\). Option C has the correct inner-surface charge but does not preserve the conductor's total charge \(Q\).
When two unequal conducting bodies are brought into contact, total charge is conserved, but why is charge not necessarily shared equally?
Correct answer: A
When conducting bodies touch, electrons redistribute until their electrical potentials reach equilibrium. Charge conservation fixes the sum of the final charges, but it does not require the two individual charges to be equal. For unequal bodies, size, shape, and capacitance can differ; at equal potential, charge generally divides in proportion to capacitance. Equal sharing is a special result for identical conductors, not a universal consequence of conservation.
In hard problems related to charge conservation, what should be done first?
Correct answer: A
The first step in a conservation problem is to define the system and decide whether it is isolated. Then identify every relevant charge and add algebraically, preserving positive and negative signs, to obtain the initial total charge Qinitial. Conservation requires Qfinal = Qinitial for that chosen system. Adding magnitudes, ignoring electron transfer, or considering only the final state can destroy the cancellation and produce an incorrect result.
In induction, if the positively charged rod is removed first and then the earth connection is removed, why may no permanent charge remain on the conductor?
Correct answer: A
Induction depends on the order of operations. A positive rod attracts electrons toward the near side, and earthing allows additional electrons to enter the conductor from Earth. If the rod is removed while the earth connection is still present, the external electric influence disappears. The conductor can then exchange electrons freely with Earth and return toward neutrality before the connection is broken. Thus option A gives the relevant mechanism; the other choices violate ordinary electrostatic behavior.
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