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In Class 12 Physics, this topic from Chapter 1, Electric Charges and Fields, explains how an electric dipole behaves when placed in a uniform external electric field. Students learn why the equal and opposite forces on the charges produce zero net force but a torque that tends to align the dipole with the field. They study the torque formula, equilibrium positions, stability, and the dipole’s potential energy, U = −p·E, using clear vector and physical interpretations.
TOPIC PRACTICE
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Up to 25 questions from this page. Select your focus, then start.
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Medium · Level 9View options
Net force is zero and torque is generally nonzero
Net force is always nonzero and torque is zero
Both net force and torque are always zero
Both net force and torque are always maximum
Medium · Level 9View options
1 : √3
√3 : 1
1 : 2
2 : 1
Medium · Level 9View options
Twice the product of dipole moment and field
Product of dipole moment and field
Zero
Half the product of dipole moment and field
Medium · Level 9View options
Thirty degrees
Sixty degrees
Ninety degrees
One hundred eighty degrees
Medium · Level 9View options
Direction that decreases the angle
Direction that increases the angle
Direction that increases separation
Direction that removes charge
Medium · Level 9View options
Equal and opposite forces act on the two charges
No force acts on either charge
Force on positive charge is larger and on negative charge is smaller
Electric field neutralizes the charges
Medium · Level 9View options
Because equal opposite forces can act along different lines
Because torque is always maximum when net force is zero
Because both charges change in the same direction
Because electric field cancels force
Medium · Level 9View options
Potential energy is minimum
Potential energy is maximum
Potential energy is always zero
Potential energy is infinite
Medium · Level 9View options
Energy is at a maximum point
Energy is at a minimum point
Energy has no meaning
Energy always remains negative
Medium · Level 9View options
Two times
Four times
Eight times
Same
Medium · Level 9View options
It becomes half
It becomes double
It becomes four times
It remains unchanged
Medium · Level 9View options
It increases
It decreases
It remains unchanged
It first decreases and then increases
Medium · Level 9View options
One by root two times
Root two times
Two times
Zero
Medium · Level 9View options
Zero degrees
Ninety degrees
One hundred eighty degrees
Sixty degrees
Medium · Level 9View options
Zero
Minimum
Maximum
Infinite
Medium · Level 9View options
When the dipole is placed at the same angle on the other side of the field
When the magnitude of the field is doubled
When the dipole moment is doubled
When the separation of charges is halved
Medium · Level 9View options
It remains the same
It becomes double
It becomes half
It becomes four times
Medium · Level 9View options
Minimum
Maximum
Zero
Infinite
Medium · Level 9View options
It remains the same
It becomes zero
It becomes double
It becomes half
Medium · Level 9View options
Because energy is maximum in this position
Because energy is minimum in this position
Because charges vanish in this position
Because the field becomes zero in this position
Medium · Level 9View options
It will be equal
It will be double
It will be half
It will be zero
Medium · Level 9View options
Both are equal
Negative at sixty degrees and positive at one hundred twenty degrees
Positive at sixty degrees and negative at one hundred twenty degrees
Both are zero
Medium · Level 9View options
Because the net force is zero
Because the torque is zero
Because the dipole moment is zero
Because no force acts on the charges
Medium · Level 9View options
Net force is zero and torque depends on angle
Net force depends on angle and torque is always zero
Net force and torque are always maximum
Net force is always perpendicular to the field
Medium · Level 9View options
Energy increases
Energy decreases
Energy remains zero
Energy becomes infinite
Question 1MediumLevel 9
Which is the most correct exam-oriented conclusion for an electric dipole in a uniform electric field?
Correct answer: A
The governing idea is the behaviour of a dipole in a uniform electric field. The positive and negative charges experience equal forces in opposite directions, so their vector sum gives zero net force. However, these forces act along different parallel lines and form a couple. Its torque is τ = pE sin θ, so it is nonzero for most orientations, but becomes zero when the dipole is exactly parallel or antiparallel to the field. Therefore A is correct; the other choices use unjustified words such as “always.”
An electric dipole is placed in a uniform electric field. If the angle between dipole moment and field is increased from thirty degrees to sixty degrees, what is the ratio of the torque values?
Correct answer: A
The torque on an electric dipole in a uniform electric field is τ = pE sin θ. For the initial angle, τ₁ = pE sin 30° = pE/2. For the final angle, τ₂ = pE sin 60° = √3pE/2. Therefore τ₁:τ₂ = (pE/2):(√3pE/2) = 1:√3, so option A is correct. The other ratios do not follow from the sine dependence.
What is the work done in slowly rotating a dipole from stable position to one hundred eighty degrees in a uniform electric field?
Correct answer: A
For a dipole in a uniform electric field, potential energy is U = −pE cos θ. The stable position is θ = 0°, where U₁ = −pE, while the opposite position is θ = 180°, where U₂ = +pE. During slow rotation, the external work equals the increase in potential energy: W = U₂ − U₁ = pE − (−pE) = 2pE. Hence option A is correct.
If the torque on a dipole in a uniform electric field is half of its maximum value, what is one possible value of the angle?
Correct answer: A
The torque is τ = pE sin θ, and its maximum value is τmax = pE when θ = 90°. If τ = τmax/2, then pE sin θ = pE/2, so sin θ = 1/2. One possible angle is 30°, although 150° is another possible angle in the usual range. Since option A gives 30°, it is the correct choice; 60° does not give half the maximum torque.
A dipole moment is placed at an obtuse angle with a uniform electric field. What kind of direction will the torque applied by the field have?
Correct answer: A
The torque on a dipole is τ = p × E, and its rotational effect tends to align the dipole moment with the electric field. Equivalently, the potential energy U = −pE cos θ decreases as the dipole turns toward θ = 0°. Therefore, even when the initial angle is obtuse, the torque acts in the direction that reduces the angle between p and E. Hence option A is correct.
What is the main reason why the net force on a dipole in a uniform electric field is zero?
Correct answer: A
A dipole contains charges +q and −q of equal magnitude. In a uniform electric field, the field has the same magnitude and direction at both charge positions. Consequently, the forces have magnitudes qE and qE but point in opposite directions. Their vector sum is zero, so the dipole has no net translational force, although the separated forces can still produce torque. Therefore option A is correct.
Why can a dipole have torque in a uniform electric field even when the net force is zero?
Correct answer: A
In a uniform field, the forces on the positive and negative charges of a dipole are equal in magnitude and opposite in direction, so their vector sum is zero. However, the charges are separated, and the two forces act along parallel but distinct lines. This pair forms a couple whose turning effect is τ = pE sin θ. Thus zero net force removes translation but not necessarily rotation, making option A correct.
When potential energy of a dipole is viewed as a function of angle, how is stable equilibrium identified?
Correct answer: A
Stable equilibrium is identified by a local minimum of potential energy. If the dipole is displaced slightly from this position, the resulting torque tends to restore it. For a dipole in a uniform electric field, U = −pE cos θ, which is minimum at θ = 0°, when the dipole moment is parallel to the field. Therefore option A is correct; maximum energy corresponds to unstable equilibrium.
How is the unstable equilibrium position of a dipole in a uniform electric field identified on the energy curve?
Correct answer: A
On a potential-energy curve, unstable equilibrium occurs at a local maximum. A small angular displacement from that point lowers the energy and produces a torque that carries the dipole farther from its original orientation. Since U = −pE cos θ, the dipole has U = +pE at θ = 180°, when its moment is opposite to the field; this is the maximum and unstable position. Thus option A is correct.
If both dipole moment and electric field are doubled while the angle remains unchanged, how many times does the torque become?
Correct answer: B
The torque on a dipole in a uniform electric field is τ = pE sin θ. If p becomes 2p and E becomes 2E while θ remains unchanged, the new torque is τ′ = (2p)(2E) sin θ = 4pE sin θ = 4τ. Therefore the torque becomes four times its original value, so option B is correct. The factor is not merely two because both independent factors are doubled.
If the dipole moment is halved and the electric field is made four times, what happens to the torque at the same angle?
Correct answer: B
The torque on an electric dipole in a uniform field is τ = pE sin θ. The angle remains unchanged, so sin θ is constant. If the dipole moment changes from p to p/2 and the field changes from E to 4E, the new torque is (p/2)(4E)sin θ = 2pE sin θ = 2τ. Therefore, the torque becomes double. It is not half or four times because both changes act together.
When a dipole is rotated from sixty degrees to one hundred twenty degrees in a uniform electric field, how does its potential energy change?
Correct answer: A
For a dipole in a uniform electric field, potential energy is U = −pE cos θ. At 60°, cos 60° = 1/2, so U is negative, equal to −pE/2. At 120°, cos 120° = −1/2, so U becomes +pE/2. Thus the energy changes from a negative value to an equal positive value and therefore increases. The distractor saying it decreases reverses this sign reasoning.
If the dipole moment makes forty-five degrees with the field, how does the magnitude of its potential energy compare with the magnitude of minimum energy?
Correct answer: A
For a dipole, U = −pE cos θ, so |U| = pE|cos θ|. The minimum energy occurs at θ = 0°, giving Umin = −pE and |Umin| = pE. At 45°, |U| = pE cos 45° = pE/√2. Therefore |U|/|Umin| = 1/√2. It is smaller than the minimum-energy magnitude, not larger or zero.
A dipole is placed in a uniform electric field such that its torque is zero but its energy is not minimum. What is the angle?
Correct answer: C
The torque on a dipole is τ = pE sin θ. For nonzero p and E, zero torque requires sin θ = 0, so θ can be 0° or 180°. The potential energy is U = −pE cos θ. At 0°, U = −pE, the minimum value; at 180°, U = +pE, the maximum value. Since the energy is explicitly not minimum, the angle must be 180°. Ninety and sixty degrees give nonzero torque.
A dipole has maximum torque in a uniform electric field. What is its potential energy at that instant?
Correct answer: A
The torque magnitude is τ = pE sin θ, so it is maximum when sin θ = 1, that is, θ = 90°. The dipole potential energy is U = −pE cos θ. Since cos 90° = 0, U = 0 at this orientation. Minimum energy occurs at 0° and maximum energy at 180°, so neither of those choices applies. The result assumes a nonzero dipole moment and field.
In a uniform electric field, in which situation does the torque on a dipole reverse its direction?
Correct answer: A
The torque on an electric dipole is given by τ = p × E, with magnitude pE sin θ. Its direction is perpendicular to both p and E and follows the right-hand rule. If the dipole is placed at the corresponding angle on the opposite side, the angular orientation changes from θ to −θ, so the cross product reverses direction. Changing only E, p, or charge separation changes magnitude, not direction.
If the magnitude of each charge is doubled and the separation is halved, what happens to torque in the same field?
Correct answer: A
The dipole moment is p = qd, and the torque magnitude is τ = pE sin θ. After the change, q′ = 2q and d′ = d/2, so p′ = q′d′ = (2q)(d/2) = qd = p. Since the electric field and angle are unchanged, τ′ = p′E sin θ equals the original torque. Thus the torque remains the same.
What is the potential energy of a dipole when it is along the direction of a uniform electric field?
Correct answer: A
The potential energy of a dipole in a uniform electric field is U = −p·E = −pE cos θ. When the dipole moment is along the field, θ = 0° and cos 0° = 1, giving U = −pE, the minimum possible value for fixed p and E. The opposite orientation gives maximum energy, while zero energy occurs at 90°, not at 0°.
If a dipole is at ninety degrees to the field and the field is suddenly reversed, what happens to the magnitude of torque?
Correct answer: A
The torque magnitude is |τ| = pE sin θ, where θ is the angle between p and E. Initially θ = 90°, so |τ| = pE. Reversing the field changes E to −E, but its magnitude remains E; the new angle is 90° or equivalently 270°, and the sine magnitude is still 1. Thus the torque magnitude remains pE, although its vector direction reverses.
Why is a dipole unstable when released opposite to a uniform electric field?
Correct answer: A
For a dipole, U = −pE cos θ. Opposite alignment means θ = 180°, so U = −pE(−1) = +pE, the maximum potential energy. Although the torque is momentarily zero at exactly 180°, a small angular displacement produces a torque that increases the displacement rather than restoring the original orientation. Hence the antiparallel position is unstable.
If a dipole makes sixty degrees with the field and the torque magnitude is known, how will the torque magnitude at one hundred twenty degrees compare?
Correct answer: A
The torque magnitude is |τ| = pE sin θ. For θ = 60°, |τ60| = pE sin 60° = (√3/2)pE. For θ = 120°, |τ120| = pE sin 120° = pE sin(180° − 60°) = (√3/2)pE. Therefore the two torque magnitudes are equal, although their vector directions may differ because the orientations are different.
If the dipole angle with the electric field is sixty degrees and one hundred twenty degrees, what is the correct comparison of potential energy?
Correct answer: B
The potential energy of a dipole in a uniform electric field is U = −pE cos θ. At θ = 60°, cos θ = 1/2, so U is negative, equal to −pE/2. At θ = 120°, cos θ = −1/2, so U is positive, equal to +pE/2. Therefore option B is correct; the signs are opposite, while neither value is zero.
Why is the acceleration of the center of a dipole considered zero in a uniform electric field?
Correct answer: A
In a uniform electric field, the positive and negative charges experience forces of equal magnitude, qE, in opposite directions. Their vector sum is therefore zero, so the translational equation M a_cm = F_net gives a_cm = 0. The forces can still form a couple and produce torque, so zero net force—not zero torque—is the reason. Option A is correct.
Which statement is correct for a dipole in a uniform electric field?
Correct answer: A
In a uniform electric field, the forces on the +q and −q charges have equal magnitude qE and opposite directions, so their vector sum gives F_net = 0 for every orientation. Because the forces act at separated points, they can form a couple with torque magnitude τ = pE sin θ. Thus torque varies with angle and is zero only at 0° and 180°. Option A is correct.
If a dipole aligned with a uniform electric field is slightly rotated, what happens to its energy?
Correct answer: A
The potential energy of an electric dipole in a uniform field is U = −pE cos θ. When the dipole is aligned with the field, θ = 0° and U is minimum, equal to −pE. A small rotation makes θ nonzero, decreases cos θ, and therefore increases U. Thus the aligned position is stable equilibrium; the energy does not remain zero or become infinite.
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