What is the value of (\sin 75^\circ\cos 15^\circ-\cos 75^\circ\sin 15^\circ)?

Question

Answer and explanation

Correct answer: ( \frac{\sqrt{3}}{2} )

This is the form of (\sin(75^\circ-15^\circ)). Hence the value is (\sin 60^\circ=\frac{\sqrt{3}}{2}).

What is the correct answer to this question?

( \frac{\sqrt{3}}{2} )

Why is this the correct answer?

This is the form of (\sin(75^\circ-15^\circ)). Hence the value is (\sin 60^\circ=\frac{\sqrt{3}}{2}).

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.