What is the range of \(f(x)=\sin x+\cos x\)?
Answer and explanation
Correct answer: \( [-\sqrt{2},\sqrt{2}] \)
We have \(\sin x+\cos x=\sqrt{2}\sin\left(x+\frac{\pi}{4}\right)\). Hence the range is \( [-\sqrt{2},\sqrt{2}] \).
Frequently asked questions
What is the correct answer to this question?
\( [-\sqrt{2},\sqrt{2}] \)
Why is this the correct answer?
We have \(\sin x+\cos x=\sqrt{2}\sin\left(x+\frac{\pi}{4}\right)\). Hence the range is \( [-\sqrt{2},\sqrt{2}] \).
Which subject and chapter does this question cover?
This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.