What is the principal radian angle for a rotation of (-\frac{11}{8}) revolution?
Answer and explanation
Correct answer: (\frac{5\pi}{4})
The rotation is (-\frac{11}{8}\times2\pi=-\frac{11\pi}{4}), and adding (4\pi) gives (\frac{5\pi}{4}). In exams, first convert revolutions into radians.
Frequently asked questions
What is the correct answer to this question?
(\frac{5\pi}{4})
Why is this the correct answer?
The rotation is (-\frac{11}{8}\times2\pi=-\frac{11\pi}{4}), and adding (4\pi) gives (\frac{5\pi}{4}). In exams, first convert revolutions into radians.
Which subject and chapter does this question cover?
This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Angles.