What is the principal angle of (-\frac{41\pi}{10}) in ([0,2\pi))?

Question

Answer and explanation

Correct answer: (\frac{19\pi}{10})

Adding (2\pi) three times to (-\frac{41\pi}{10}) gives (\frac{19\pi}{10}). In exams, keep adding (2\pi) until the angle enters the interval.

What is the correct answer to this question?

(\frac{19\pi}{10})

Why is this the correct answer?

Adding (2\pi) three times to (-\frac{41\pi}{10}) gives (\frac{19\pi}{10}). In exams, keep adding (2\pi) until the angle enters the interval.

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Angles.