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What is the period of the function (\sin 3x)?

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Answer and explanation

Correct answer: \(\frac{2\pi}{3}\)

The period of (\sin kx) is \(\frac{2\pi}{k}\). Here \(k=3\), so the period is \(\frac{2\pi}{3}\).

Tags

periodsinetransformation

Frequently asked questions

What is the correct answer to this question?

\(\frac{2\pi}{3}\)

Why is this the correct answer?

The period of (\sin kx) is \(\frac{2\pi}{k}\). Here \(k=3\), so the period is \(\frac{2\pi}{3}\).

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.

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