What is the minimum value of (\sin \theta-\cos \theta)?
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Answer and explanation
Correct answer: (-\sqrt{2})
The amplitude of ( \sin \theta-\cos \theta) is ( \sqrt{1^2+(-1)^2}=\sqrt{2}). In exams the minimum is the negative amplitude.
Frequently asked questions
What is the correct answer to this question?
(-\sqrt{2})
Why is this the correct answer?
The amplitude of ( \sin \theta-\cos \theta) is ( \sqrt{1^2+(-1)^2}=\sqrt{2}). In exams the minimum is the negative amplitude.
Which subject and chapter does this question cover?
This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.
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