What is the maximum value of the function (3\sin x+1)?
Answer and explanation
Correct answer: 4
Since \(\sin x\) lies between \(-1\) and \(1\), its maximum value is \(1\). Therefore, the maximum of \(3\sin x+1\) is \(3\times1+1=4\). Option 3 is only the maximum of \(3\sin x\); adding the constant \(1\) shifts the maximum to 4. Exam tip: for \(a\sin x+b\), when \(a>0\), the maximum value is \(a+b\).
Frequently asked questions
What is the correct answer to this question?
4
Why is this the correct answer?
Since \(\sin x\) lies between \(-1\) and \(1\), its maximum value is \(1\). Therefore, the maximum of \(3\sin x+1\) is \(3\times1+1=4\). Option 3 is only the maximum of \(3\sin x\); adding the constant \(1\) shifts the maximum to 4. Exam tip: for \(a\sin x+b\), when \(a>0\), the maximum value is \(a+b\).
Which subject and chapter does this question cover?
This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.
