What is the fundamental period of (\sin 3\theta)?
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Answer and explanation
Correct answer: (\frac{2\pi}{3})
The period of ( \sin k\theta) is ( \frac{2\pi}{k}), so here it is ( \frac{2\pi}{3}). In exams use the coefficient in the period formula.
Frequently asked questions
What is the correct answer to this question?
(\frac{2\pi}{3})
Why is this the correct answer?
The period of ( \sin k\theta) is ( \frac{2\pi}{k}), so here it is ( \frac{2\pi}{3}). In exams use the coefficient in the period formula.
Which subject and chapter does this question cover?
This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.
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