If (x) is in the third quadrant and (\tan x=\frac{9}{40}), what is the value of (\sec x)?

Question

Answer and explanation

Correct answer: (-\frac{41}{40})

From (\sec^2 x=1+\tan^2 x), (|\sec x|=\frac{41}{40}). In the third quadrant, (\sec x) is negative.

What is the correct answer to this question?

(-\frac{41}{40})

Why is this the correct answer?

From (\sec^2 x=1+\tan^2 x), (|\sec x|=\frac{41}{40}). In the third quadrant, (\sec x) is negative.

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.