If (x) is in the third quadrant and (\sin x=-\frac{5}{13}), what is the value of (\sec x)?

Question

Answer and explanation

Correct answer: -(\frac{13}{12}) / (-\frac{13}{12})

In the third quadrant, (\cos x) is negative. Since (\cos x=-\frac{12}{13}), (\sec x=-\frac{13}{12}).

What is the correct answer to this question?

-(\frac{13}{12}) / (-\frac{13}{12})

Why is this the correct answer?

In the third quadrant, (\cos x) is negative. Since (\cos x=-\frac{12}{13}), (\sec x=-\frac{13}{12}).

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.