If ( \theta ) is in the fourth quadrant and the reference angle is ( \frac{\pi}{9} ), what is the principal radian value of ( \theta )?

Question

Answer and explanation

Correct answer: ( \frac{17\pi}{9} )

In the fourth quadrant ( \theta=2\pi-\frac{\pi}{9}=\frac{17\pi}{9} ). A full revolution in radians is (2\pi).

What is the correct answer to this question?

( \frac{17\pi}{9} )

Why is this the correct answer?

In the fourth quadrant ( \theta=2\pi-\frac{\pi}{9}=\frac{17\pi}{9} ). A full revolution in radians is (2\pi).

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Angles.