If (\theta) is in the fourth quadrant and (\cos \theta=\frac{8}{17}), what will (\tan \theta) be?

Question

Answer and explanation

Correct answer: (-\frac{15}{8} )

In the fourth quadrant, (\sin \theta) is negative and (\cos \theta) is positive. Hence (\sin \theta=-\frac{15}{17}) and (\tan \theta=-\frac{15}{8}).

What is the correct answer to this question?

(-\frac{15}{8} )

Why is this the correct answer?

In the fourth quadrant, (\sin \theta) is negative and (\cos \theta) is positive. Hence (\sin \theta=-\frac{15}{17}) and (\tan \theta=-\frac{15}{8}).

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.