If (\tan x=\frac{1}{2}), what is the value of (\frac{1-\tan^2 x}{1+\tan^2 x})?
Answer and explanation
Correct answer: (\frac{3}{5})
Put (\tan^2 x=\frac{1}{4}). Then the value is (\frac{1-\frac{1}{4}}{1+\frac{1}{4}}=\frac{3}{5}).
Frequently asked questions
What is the correct answer to this question?
(\frac{3}{5})
Why is this the correct answer?
Put (\tan^2 x=\frac{1}{4}). Then the value is (\frac{1-\frac{1}{4}}{1+\frac{1}{4}}=\frac{3}{5}).
Which subject and chapter does this question cover?
This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.