If (\sin x+\sin^2 x=0), how many solutions are there in (0\leq x<2\pi)?

Since (\sin x(1+\sin x)=0), (\sin x=0) or (\sin x=-1). In the given interval, (x=0,\pi,\frac{3\pi}{2}).

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.

Answer and explanation

Correct answer: (3)

Since (\sin x(1+\sin x)=0), (\sin x=0) or (\sin x=-1). In the given interval, (x=0,\pi,\frac{3\pi}{2}).

What is the correct answer to this question?

(3)

Why is this the correct answer?

Since (\sin x(1+\sin x)=0), (\sin x=0) or (\sin x=-1). In the given interval, (x=0,\pi,\frac{3\pi}{2}).

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.