How can (\frac{1+\sin x}{1-\sin x}) be written in terms of (\sec x) and (\tan x)?

Question

Answer and explanation

Correct answer: ((\sec x+\tan x)^2)

Rationalising the denominator gives (\frac{(1+\sin x)^2}{\cos^2 x}). This equals ((\sec x+\tan x)^2).

What is the correct answer to this question?

((\sec x+\tan x)^2)

Why is this the correct answer?

Rationalising the denominator gives (\frac{(1+\sin x)^2}{\cos^2 x}). This equals ((\sec x+\tan x)^2).

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Trigonometric functions and their properties.