A ray first turns (\frac{17\pi}{6}) counterclockwise and then (\frac{5\pi}{3}) clockwise. What is the final principal angle?

Question

Answer and explanation

Correct answer: (\frac{7\pi}{6})

The net angle is (\frac{17\pi}{6}-\frac{5\pi}{3}=\frac{7\pi}{6}). Take counterclockwise as positive and clockwise as negative.

What is the correct answer to this question?

(\frac{7\pi}{6})

Why is this the correct answer?

The net angle is (\frac{17\pi}{6}-\frac{5\pi}{3}=\frac{7\pi}{6}). Take counterclockwise as positive and clockwise as negative.

Which subject and chapter does this question cover?

This is a Class 12 Mathematics question. Chapter: Trigonometric Functions. Topic: Angles.