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If (\sin x+\sin^2 x=0), how many solutions are there in (0\leq x<2\pi)?यदि (\sin x+\sin^2 x=0), तो (0\leq x<2\pi) में कितने हल हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3)(3)
Since (\sin x(1+\sin x)=0), (\sin x=0) or (\sin x=-1). In the given interval, (x=0,\pi,\frac{3\pi}{2}).(\sin x(1+\sin x)=0), इसलिए (\sin x=0) या (\sin x=-1)। दिए गए अंतराल में (x=0,\pi,\frac{3\pi}{2}) मिलते हैं।
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