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If (\cos x=-\frac{1}{2}), what are the values of (x) in (0\leq x<2\pi)?यदि (\cos x=-\frac{1}{2}), तो (0\leq x<2\pi) में (x) के मान कौन-से हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \frac{2\pi}{3},\frac{4\pi}{3} )( \frac{2\pi}{3},\frac{4\pi}{3} )
(\cos x) is negative in the second and third quadrants. Hence (x=\frac{2\pi}{3},\frac{4\pi}{3}).(\cos x) द्वितीय और तृतीय चतुर्थांश में ऋणात्मक होता है। इसलिए (x=\frac{2\pi}{3},\frac{4\pi}{3})।
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