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If (x) is in the second quadrant and (\sin x=\frac{5}{13}), what will (\cos x) be?यदि (x) द्वितीय चतुर्थांश में है और (\sin x=\frac{5}{13}), तो (\cos x) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-\frac{12}{13} )(-\frac{12}{13} )
In the second quadrant, (\cos x) is negative. From (\sin^2 x+\cos^2 x=1), (\cos x=-\frac{12}{13}).द्वितीय चतुर्थांश में (\cos x) ऋणात्मक होता है। (\sin^2 x+\cos^2 x=1) से (\cos x=-\frac{12}{13})।
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