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Class 12MathematicsTrigonometric FunctionsTrigonometric functions and their propertiesHard
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What is the product form of (\cos 4x-\cos 2x)?

Answer and explanation

Correct answer: (-2\sin 3x\sin x)

The formula is (\cos A-\cos B=-2\sin\frac{A+B}{2}\sin\frac{A-B}{2}). Hence the answer is (-2\sin 3x\sin x).

Related tags

Trigonometric-FunctionsSum-To-ProductCosineTrigonometric Functions And Their PropertiesTrigonometric FunctionsMathematicsClass 12 Mcq
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10 more MCQs
  1. 1If \(\theta=0^\circ\), what is the value of \(\sin \theta\)?
  2. 2If \(\theta=0^\circ\), what is the value of \(\cos \theta\)?
  3. 3If \(\theta=45^\circ\), what is the value of \(\tan \theta\)?
  4. 4Which trigonometric function is the reciprocal of \(\sin \theta\)?
  5. 5Which trigonometric function is the reciprocal of (\cos \theta)?
  6. 6Which trigonometric function is the reciprocal of \(\tan\theta\)?
  7. 7What is (\tan \theta) equal to?
  8. 8What is (\cot \theta) equal to?
  9. 9What is the value of the basic identity (\sin^2 \theta+\cos^2 \theta)?
  10. 10What is the value of (\sec^2 \theta-\tan^2 \theta)?
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